For A Freely Falling Object Dropped From The Rest What Is Its Acceleration At The End Of Fifth Second Of Its Fall?

For a freely falling object dropped from the rest what is its acceleration at the end of fifth second of its fall?

 

Velocity is the rate of change of displacement.  

Acceleration is the rate of change of velocity.  

According to Newtons equation F=ma, at constant velocity, acceleration is zero. Recall that acceleration is the rate of change of velocity. If velocity is constant, there is no change in acceleration. Thus net force is 0.  

For a free falling object, acceleration depends on the mass on the object and resultant force acting on it. Acceleration due to gravity, 9.81m/s^2, assuming air resistance is negligible, will act on the object until it reaches max velocity. It will reach a point of maximum (terminal) velocity and acceleration will be equals to zero.  

Time taken to reach the top is the time taken for the final velocity to be zero.  

Using the equation v^2=u^2 + 2as, where s is displacement and a is acceleration due to gravity, and v and u are final and initial velocities respectively, taking upwards motion to be positive since acceleration is a vector,  

v=0  

u=30  

hence 30^2 + 2(-9.81)s = 0.  

Therefore s = 46. Im assuming you take acceleration due to gravity to be 10 thats why you got 45.  

Use v = u + at to find t which will be 3s.  


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