Find X In The Equation S^2+8s+12

Find x in the equation s^2+8s+12


 {s}^{2}  + 8s + 12 = 0 \\ (s + 6)(s + 2) = 0 \\ s + 6 = 0 \\ s =  - 6 \\ s + 2 = 0 \\ s =  - 2
Therefore there are 2 possible values of s(not x)
s= -6 & s= -2

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